Hello Rodrigo,
I have been looking into your ‘MinHoursRoster’, which does exactly what it is supposed do to. However, realistic workforce planning is conducted most often on a weekly basis. Therefore, I would like o ask you to create a ‘WeeklyRoster’ tool that would look like the existing ‘MinHoursRoster’ but with following three major differences :
Instead of a number of days, the user should be able to create a roster based on a number of weeks (each week made up of 7 days)
When entering a number of ‘max_rest’ days (from 0 as no resting day and 7 as the maximum number of resting days per week), whenever the ‘max_rest’ days >= 2, such two resting days should be combined to simulate the weekend (or its replacing two days) according to a revolving scheme to be calculated by the logic. I think this could be done by adapting your ‘MinHoursRoster’ code as follows :
def optimize_max_resting(shifts, num_days, max_resting):
resting_days = 0
for i in range(num_days):
if shifts[i] == 0:
resting_days += 1
if resting_days >= 2:
return True
else:
resting_days = 0
if max_resting > 2:
return True
return False
Finally, the shifts should remain stable throughout the week for each individual resource (and not having such a resource switch between 2, 3 or even 4 shifts (or more) during the days he/she will be planned for each week. E.g. someone should work 5 days the same shift during the same week in which he/she has 2 resting days. Next week this could be another shift, but always the same shift within this second week, and so on. I think this could be done by adapting your ‘MinHoursRoster’ code as follows :
def optimize_shifts(shifts, max_consecutive_shifts):
consecutive_shifts = 0
for i in range(len(shifts)):
if shifts[i] == 1:
consecutive_shifts += 1
if consecutive_shifts >= max_consecutive_shifts:
if i + 1 < len(shifts) and shifts[i + 1] == 0:
consecutive_shifts = 0
else:
return False
else:
consecutive_shifts = 0
return True
I am not proficient enough to start tampering with your code, but it would be greatly appreciated if you could look into this. Creating a ‘WeeklyRoster’ tool would be a great addition to pyworkforce, I think since it would mimic more closely real life situations.
Hello Rodrigo,
I have been looking into your ‘MinHoursRoster’, which does exactly what it is supposed do to. However, realistic workforce planning is conducted most often on a weekly basis. Therefore, I would like o ask you to create a ‘WeeklyRoster’ tool that would look like the existing ‘MinHoursRoster’ but with following three major differences :
Instead of a number of days, the user should be able to create a roster based on a number of weeks (each week made up of 7 days)
When entering a number of ‘max_rest’ days (from 0 as no resting day and 7 as the maximum number of resting days per week), whenever the ‘max_rest’ days >= 2, such two resting days should be combined to simulate the weekend (or its replacing two days) according to a revolving scheme to be calculated by the logic. I think this could be done by adapting your ‘MinHoursRoster’ code as follows :
def optimize_max_resting(shifts, num_days, max_resting):
resting_days = 0
for i in range(num_days):
if shifts[i] == 0:
resting_days += 1
if resting_days >= 2:
return True
else:
resting_days = 0
if max_resting > 2:
return True
return False
Finally, the shifts should remain stable throughout the week for each individual resource (and not having such a resource switch between 2, 3 or even 4 shifts (or more) during the days he/she will be planned for each week. E.g. someone should work 5 days the same shift during the same week in which he/she has 2 resting days. Next week this could be another shift, but always the same shift within this second week, and so on. I think this could be done by adapting your ‘MinHoursRoster’ code as follows :
def optimize_shifts(shifts, max_consecutive_shifts):
consecutive_shifts = 0
for i in range(len(shifts)):
if shifts[i] == 1:
consecutive_shifts += 1
if consecutive_shifts >= max_consecutive_shifts:
if i + 1 < len(shifts) and shifts[i + 1] == 0:
consecutive_shifts = 0
else:
return False
else:
consecutive_shifts = 0
return True
I am not proficient enough to start tampering with your code, but it would be greatly appreciated if you could look into this. Creating a ‘WeeklyRoster’ tool would be a great addition to pyworkforce, I think since it would mimic more closely real life situations.