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87 changes: 87 additions & 0 deletions tree-bst/108.md
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- 問題: [108. Convert Sorted Array to Binary Search Tree](https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/)
- 条件
- `1 <= nums.length <= 10^4`
- `-10^4 <= nums[i] <= 10^4`
- `nums is sorted in a strictly increasing order.`
- 方針
- 再帰関数というか、2分探索
- int middle = nums.length / 2 を真ん中とする
- 0 ~ middle までを左に振り
- middle + 1 ~ nums.length までを右に振る
- 上記をひたすら繰り返す
- 時間計算量: `O(log n)`
- 空間計算量: TreeNode を nums.length - 1 分作るので、`O(N)`, 再帰の深さは`O(log n)`
- 時間: 10分

```java
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode sortedArrayToBST(int[] nums) {
if (nums.length == 0) {
return null;
}
return createTreeNode(nums, 0, nums.length);
}

private TreeNode createTreeNode(int[] nums, int left, int right) {
if (right <= 0 || left >= right) {
return null;
}

int middle = (left + right) / 2;
TreeNode root = new TreeNode(nums[middle]);
root.left = createTreeNode(nums, left, middle);
root.right = createTreeNode(nums, middle + 1, right);

return root;
}
}
```
- 条件が冗長だったので書き直し
```java
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode sortedArrayToBST(int[] nums) {
return createBST(nums, 0, nums.length);
}

private TreeNode createBST(int[] nums, int left, int right) {
if (left >= right) {
return null;
}
int middle = (left + right) / 2;

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int middle = left + (right - left) / 2; とするとオーバーフロー対策にはなりそうです

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ありがとうございます、極端に大きい nums について考える時はおっしゃる通り、その通りです。
今回の問題は 10^4 が最大値なので、コールスタックに積むのは14程度になるので問題としては考慮不要として解いていました。

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失礼しました。
ここでいただいている指摘は整数オーバーフローの方ですね。制約の通り、この問題ではオーバーフローしませんが、日常的に書いておくべきことだと思いました。
ありがとうございます。

TreeNode newNode = new TreeNode(nums[middle]);
newNode.left = createBST(nums, left, middle);
newNode.right = createBST(nums, middle + 1, right);
return newNode;
}
}
```