0401프로그래머스#33
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0401프로그래머스 문제 1번,2번
ghost
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ghost
reviewed
Mar 31, 2022
| if(number == 0) return false; | ||
| if(number == 1) return false; | ||
| if(number == 2) return true; | ||
| for(int i = 3; i<=Math.sqrt(number); i = i+2) { |
ghost
reviewed
Mar 31, 2022
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| String sector = ""; | ||
| for(int i = 0; i<change.length();i++) { | ||
| if(change.charAt(i) != '0') sector += change.charAt(i); |
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String에 + 연산이 많아질거 같은 경우에는 StringBuilder를 사용하는 것을 권장합니다 !
Kuuuna98
reviewed
Mar 31, 2022
| if(number == 0) return false; | ||
| if(number == 1) return false; | ||
| if(number == 2) return true; | ||
| for(int i = 3; i<=Math.sqrt(number); i = i+2) { |
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for문이 반복할 때마다 조건문을 확인하기 때문에, 매번 Math.sqrt() 함수가 실행됩니다
변수로 저장해서 사용하면 sqrt함수 실행을 한번만 하기 때문에 시간적으로 더 좋은 코드가 될 수 있을 거라 생각합니다~~!😺
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0401프로그래머스 문제 1번,2번