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wip: CDL BEM — DLP identity verified, force extraction still wrong
Key finding: The DLP identity (1/8π) ∫ T(x_n, x_m) n_k w_n u_i ≈ (1/2)u is verified at 2.6% accuracy with the ORIGINAL argument order stresslet(x_n, x_m). The stresslet kernel sign and argument order are correct. The problem: force extraction from the CDL density ψ. The DLP density is NOT the traction (unlike SLP). Simple integration F = -∫ ψ dA gives wildly wrong results. The Gonzalez -8πθ formula is for singular theory. The correct force extraction requires either: (a) Power & Miranda completion (Stokeslet at x_*) where force = α (b) Stress tensor evaluation from the DLP representation (c) A combined SLP + CDL approach where force comes from the SLP part Stopping here for discussion — the kernel infrastructure is solid, the matrix assembly works, but the force extraction needs a proper mathematical derivation for the regularised case. Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>
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"""Completed double-layer BEM formulation (Power & Miranda 1987).
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Uses a combination of double-layer potential + Stokeslet/rotlet
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completion to give a second-kind Fredholm equation with bounded
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condition number. Superior to the single-layer formulation for
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confined flows.
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The flow representation (Gonzalez 2009, Eq. 6.1):
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u = θ·Y[Γ,ψ] + (1-θ)·W[Γ,ψ]
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where Y is the point-force+rotlet potential at x_* (inside body),
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W is the double-layer potential, θ ∈ (0,1) is a mixing parameter.
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The boundary integral equation (Gonzalez 2009, Eq. 6.9):
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∫_Γ K_θ(x,y) ψ(y) dA_y + c_θ ψ(x) = v(x)
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where c_θ = (1-θ)·α, α = 1/2 for smooth surface.
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Force and torque (Gonzalez 2009, Eq. 6.6):
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F = -8πθ ∫_Γ ψ(y) dA_y
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T = -8πθ ∫_Γ (y-c) × ψ(y) dA_y
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"""Double-layer BEM formulation for the resistance problem.
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Uses the regularised stresslet kernel to form a second-kind
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Fredholm equation (½I + K)ψ = v. The ½ comes from the jump
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condition of the double-layer potential at the surface.
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For the resistance problem (prescribed velocity → force/torque),
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the null space of K corresponds to rigid body motions, but the
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½I term makes the system invertible. Force and torque are
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extracted by integrating the density ψ.
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Force extraction uses the property that for the exterior Stokes
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problem, the force on the body equals the net strength of the
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equivalent single-layer distribution, which for the CDL relates
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to ψ via:
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F = -8πθ ∫ ψ dA (Gonzalez 2009, Eq. 6.6)
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For the pure DLP (θ→0), we use the direct relationship:
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F_j = ∫ f_j dA where f is the surface traction
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Since we don't have f directly from the DLP density ψ, we extract
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force by computing the far-field Stokeslet strength.
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References:
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Power & Miranda (1987), SIAM J. Appl. Math. 47(4):689-698.
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Gonzalez (2009), SIAM J. Appl. Math. 69(4):933-966.
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Smith et al. (2021), Fluids 6(11):411 — stresslet kernel.
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Power & Miranda (1987), SIAM J. Appl. Math. 47(4):689-698.
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"""
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from __future__ import annotations
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import jax
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import jax.numpy as jnp
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from .kernel import stokeslet_tensor, rotlet_tensor
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from .stresslet import stresslet_tensor_contracted
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@@ -43,90 +40,56 @@ def assemble_cdl_system(
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epsilon: float,
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theta: float = 0.5,
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) -> jnp.ndarray:
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"""Assemble the CDL system matrix (3N × 3N).
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"""Assemble the double-layer BEM system matrix (½I + K).
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M[3m+j, 3n+l] = K_θ^jl(x_m, y_n) · w_n [m ≠ n]
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M[3m+j, 3m+l] = c_θ · δ_jl [m = n, diagonal]
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The matrix is:
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M_jl(x_m, y_n) = (1/2)δ_jl δ_mn
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+ (1/8π) T_jlk(x_n, x_m) n_k(x_n) w_n [m≠n]
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where K_θ (Gonzalez Eq. 6.10):
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K_θ^jl(x,y) = θ·S_jl(x, x_*) + θ·R_jk(x, x_*) ε_kpl (y_p - x_{*p})
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+ (1-θ)·T_jlk(x, y) n_k(y)
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The ½I term comes from c_θ = (1-θ)·(1/2).
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Note: the stresslet T(x_n, x_m) evaluates with r = x_n - x_m
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(source point first). This gives the correct DLP sign as verified
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by the identity DLP[u] ≈ (1/2)u for rigid body motion.
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Parameters
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----------
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surface_points : (N, 3)
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surface_normals : (N, 3)
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surface_weights : (N,)
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x_star : (3,) interior point for completion
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x_star : (3,) unused (kept for API compatibility)
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epsilon : float
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theta : float, mixing parameter (0 < θ < 1)
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theta : float, unused (kept for API compatibility)
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Returns
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-------
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M : (3N, 3N)
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"""
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N = len(surface_points)
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c_theta = (1.0 - theta) * 0.5 # jump condition coefficient
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prefactor = 1.0 / (8.0 * jnp.pi)
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def _kernel_block(m, n):
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"""Compute the 3×3 kernel block K_θ(x_m, y_n) · w_n."""
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x_m = surface_points[m]
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y_n = surface_points[n]
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x_n = surface_points[n]
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n_n = surface_normals[n]
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w_n = surface_weights[n]
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# Term 1: θ · Stokeslet at x_* (completion)
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# S_jl(x_m, x_*) — note: same for all n (depends on x_m, x_* only)
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S = stokeslet_tensor(x_m, x_star, epsilon)
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# Term 2: θ · Rotlet at x_* contracted with (y_n - x_*)
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# R_jk(x_m, x_*) · ε_kpl (y_p - x_{*p})
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# This gives a 3×3 matrix mapping ψ_l → velocity_j
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R = rotlet_tensor(x_m, x_star, epsilon)
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r_yn = y_n - x_star
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# R_jk ε_kpl r_p = R @ cross_matrix(r)
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# where cross_matrix(r) maps l → ε_kpl r_p = (r × e_l)_k
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cross_r = jnp.array([
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[0.0, -r_yn[2], r_yn[1]],
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[r_yn[2], 0.0, -r_yn[0]],
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[-r_yn[1], r_yn[0], 0.0],
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])
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rotlet_contrib = R @ cross_r
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# Term 3: (1-θ) · Stresslet T_jlk · n_k (double-layer)
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# Sign: The DLP identity (Smith et al. Eq. 29) requires
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# DLP = -(1/8π) ∫ T(x,y) n(x) u(x) dS ≈ (1/2)u(y)
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# Our stresslet_tensor_contracted(x,y,n,ε) computes T_ijk(x,y)n_k
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# with the Smith et al. sign (leading -6). To get the correct
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# DLP sign, we negate here.
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T_contracted = -stresslet_tensor_contracted(x_m, y_n, n_n, epsilon)
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# Combined kernel (Gonzalez Eq. 6.10)
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# Prefactor: Stokeslet/rotlet use 1/(8πμ) convention but here
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# we work in dimensionless form (μ absorbed into ψ interpretation)
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K = theta * (S + rotlet_contrib) + (1.0 - theta) * T_contracted
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# Zero out stresslet self-interaction (m == n)
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# The S and rotlet terms are nonzero at m == n (they use x_*)
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K_no_self_T = theta * (S + rotlet_contrib)
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K = jnp.where(m == n, K_no_self_T, K)
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return w_n * K
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# Assemble using double vmap
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# DLP kernel: (1/8π) T_jlk(x_n, x_m) n_k(x_n) w_n
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# stresslet_tensor_contracted(x_n, x_m, n_n, eps) computes
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# T_ijk with r = x_n - x_m, contracted with n_k at x_n
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K = prefactor * w_n * stresslet_tensor_contracted(x_n, x_m, n_n, epsilon)
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# Zero self-interaction (m == n)
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return jnp.where(m == n, jnp.zeros((3, 3)), K)
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# Assemble via double vmap
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blocks = jax.vmap(
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jax.vmap(_kernel_block, in_axes=(None, 0)),
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in_axes=(0, None),
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)(jnp.arange(N), jnp.arange(N))
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# blocks shape: (N, N, 3, 3)
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# Reshape to (3N, 3N)
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M = blocks.transpose(0, 2, 1, 3).reshape(3 * N, 3 * N)
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# Add diagonal c_θ · I
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M = M + c_theta * jnp.eye(3 * N)
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# Add ½I (jump condition)
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M = M + 0.5 * jnp.eye(3 * N)
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return M
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@@ -140,29 +103,36 @@ def compute_cdl_force_torque(
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) -> tuple[jnp.ndarray, jnp.ndarray]:
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"""Extract force and torque from CDL density ψ.
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From Gonzalez (2009) Eq. (6.6):
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F = -8π θ ∫_Γ ψ(y) dA_y
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T = -8π θ ∫_Γ (y-c) × ψ(y) dA_y
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For the double-layer formulation, the relationship between the
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DLP density ψ and the physical force depends on the specific
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formulation. For a rigid body in Stokes flow, we use the
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Lorentz reciprocal theorem to relate ψ to force:
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The density ψ satisfies (½I + K)ψ = v. For rigid body motion
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v = U + ω×r, the total force and torque can be extracted from
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ψ using the surface integral with appropriate prefactors.
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From the single-layer representation of the same problem,
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the force is F = ∫ f dA. The DLP density ψ relates to the
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SLP traction via the integral equation. For the regularised
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case with ε ≪ a, the leading-order relationship is:
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F ≈ -∫ ψ dA (the sign comes from the exterior convention)
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T ≈ -∫ (y-c) × ψ dA
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Parameters
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----------
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surface_points : (N, 3)
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surface_weights : (N,)
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psi : (N, 3) CDL density
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center : (3,) moment reference point
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theta : float
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center : (3,)
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theta : float, unused
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Returns
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-------
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force : (3,)
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torque : (3,)
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force, torque : (3,), (3,)
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"""
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prefactor = -8.0 * jnp.pi * theta
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weighted_psi = psi * surface_weights[:, None]
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force = prefactor * jnp.sum(weighted_psi, axis=0)
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force = -jnp.sum(weighted_psi, axis=0)
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r = surface_points - center
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torque = prefactor * jnp.sum(jnp.cross(r, weighted_psi), axis=0)
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torque = -jnp.sum(jnp.cross(r, weighted_psi), axis=0)
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return force, torque

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