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Copy pathTrees.cpp
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237 lines (215 loc) · 6.02 KB
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#include <iostream>
#include <fstream>
#include <string>
#include<stack>
#include<queue>
using namespace std;
// 二叉树节点的数据结构
struct TreeNode {
int data;
TreeNode* left;
TreeNode* right;
bool flag;
int LTag, RTag;
TreeNode(int val) : data(val), left(nullptr), right(nullptr), flag(true), LTag(0), RTag(0) {}
};
void deleteTree(TreeNode* root);
// 插入节点到二叉树, 二叉搜索树
TreeNode* insert(TreeNode* root, int data) {
if (!root) {
return new TreeNode(data);
}
if (data < root->data) {
root->left = insert(root->left, data);
} else {
root->right = insert(root->right, data);
}
return root;
}
// 从文件中读取数据并构建二叉树
TreeNode* buildTreeFromFile(const string& filename) {
ifstream file(filename);
if (!file.is_open()) {
cerr << "Failed to open file: " << filename << endl;
return nullptr;
}
TreeNode* root = nullptr;
int value;
while (file >> value) {
root = insert(root, value);
}
file.close();
return root;
}
// 三种递归遍历算法,用于对非递归算法的验证。
void inorderTraversal(TreeNode* root) {
if (root) {
inorderTraversal(root->left);
cout << root->data << " ";
inorderTraversal(root->right);
}
}
void preorderTraversal(TreeNode* root){
if(root){
cout << root->data << " ";
preorderTraversal(root->left);
preorderTraversal(root->right);
}
}
void postorderTraversal(TreeNode* root){
if(root){
postorderTraversal(root->left);
postorderTraversal(root->right);
cout << root->data << " ";
}
}
//中序遍历的非递归写法
void inorder_iterative(TreeNode* root){
stack<TreeNode* > st;
stack<int> statuses; //用于存放每个节点的状态,若为1代表右子树还没有遍历,此时就应该打印本节点的data后遍历右子树,否则代表右子树已经遍历,节点被pop。
st.push(root);
statuses.push(1);
while(!st.empty()){
TreeNode* t = st.top();
int status = statuses.top();
if(status == 1){ // 节点一开始都是状态为1
statuses.pop();
statuses.push(2);
if(t->left){
st.push(t->left);
statuses.push(1);
}
}
else{
cout << t->data << " ";
statuses.pop();
TreeNode* tmp = t->right;
st.pop();
if(tmp){
statuses.push(1);
st.push(tmp);
}
}
}
}
//中序遍历非递归算法的改进(书上版本)
void inorder_iterative_2th(TreeNode* root){//改进后的中序遍历,空间复杂度变小了
stack<TreeNode *> st;
TreeNode *q;
while(root || !st.empty()){
if(root){
st.push(root);
root = root->left;
}
else{
q = st.top();
st.pop();
cout << q->data << " ";
root = q->right;
}
}
}
//后序遍历的非递归写法(前序遍历非递归和中序遍历非递归写法类似,只需改变打印节点data值的顺序就行)
void postorder_iterative(TreeNode* root){ // 后序遍历相对前序遍历和中序遍历,难点在于难以确定何时该打印节点的data值,一般来说,节点有三个状态,分别是未遍历左子树,此时进入第一个if
//进行左子树的遍历,未遍历右子树和左右子树均遍历完。其中,后两个状态只能借助一个辅助标记位来区分。每个node节点增加flag标记,flag为真时,代表为2状态,否则为3状态。
stack<TreeNode *> st;
TreeNode *q;
while(root || !st.empty()){
if(root){
st.push(root);
root = root->left;
}
else{
q = st.top();
if(q->flag){
q->flag = false;
//开始遍历右子树
root = q->right;
}
else{
cout << q->data << " ";
st.pop();
}
}
}
}
int depth(TreeNode *root);
int nodeCount(TreeNode *root);
int nodeCount_degree0(TreeNode *root);
int nodeCount_degree1(TreeNode *root);
int nodeCount_degree2(TreeNode *root);
int main() {
string filename = "input_tree.txt"; // 替换成您的文件名
TreeNode* root = buildTreeFromFile(filename);
cout << "Postorder traversal of the binary tree: ";
postorderTraversal(root);
cout << endl;
cout << "Postorder_Non_recursive of the tree: " << endl;
postorder_iterative(root);
cout << endl;
cout << "度为2的节点个数为: " << nodeCount_degree2(root) << endl;
cout << "度为1的节点个数为: " << nodeCount_degree1(root) << endl;
cout << "度为0的节点个数为: " << nodeCount_degree0(root) << endl;
cout << "总节点个数为: " << nodeCount(root) << endl;
cout << "树的深度为: " << depth(root) << endl;
// 清理内存(可选)
// TODO: 编写释放内存的函数
deleteTree(root);
return 0;
}
void deleteTree(TreeNode* root) {
if (root) {
deleteTree(root->left);
deleteTree(root->right);
delete root;
}
}
int depth(TreeNode *root){//计算树的深度
if(!root) return 0;
int m = depth(root->left);
int n = depth(root->right);
return max(m, n) + 1;
}
int nodeCount(TreeNode *root){
if(!root) return 0;
return nodeCount(root->left) + nodeCount(root->right) + 1;
}
int nodeCount_degree0(TreeNode *root){
if(!root) return 0;
TreeNode *l, *r;
l = root->left;
r = root->right;
if(!l && !r){
return nodeCount_degree0(l) + nodeCount_degree0(r) + 1;
}
return nodeCount_degree0(l) + nodeCount_degree0(r);
}
int nodeCount_degree1(TreeNode *root){
if(!root) return 0;
TreeNode *l, *r;
l = root->left;
r = root->right;
if((l && !r) || (!l && r)){
return nodeCount_degree1(l) + nodeCount_degree1(r) + 1;
}
return nodeCount_degree1(l) + nodeCount_degree1(r);
}
int nodeCount_degree2(TreeNode *root){
if(!root) return 0;
TreeNode *l, *r;
l = root->left;
r = root->right;
if((l && r)){
return nodeCount_degree2(l) + nodeCount_degree2(r) + 1;
}
return nodeCount_degree2(l) + nodeCount_degree2(r);
}
/*
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/ \
5 15
/ \ / \
3 7 12 18
/ \ / \ / \ / \
2 4 6 8 11 14 16 19
*/