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Copy pathPascalsTriangleII.js
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64 lines (54 loc) 路 1.19 KB
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/**
* Given an index k, return the kth row of the Pascal's triangle.
*
* For example, given k = 3,
* Return [1,3,3,1].
*
* Note:
* Could you optimize your algorithm to use only O(k) extra space?
*
* Accepted.
*/
/**
* @param {number} rowIndex
* @return {number[]}
*/
let getRow = function (rowIndex) {
let results = [];
results.push(1);
if (rowIndex === 0) {
return results;
}
for (let i = 0; i < rowIndex; i++) {
results.push(1);
for (let j = results.length - 2; j > 0; j--) {
results[j] = results[j - 1] + results[j];
}
}
return results;
};
if (getRow(0).toString() === [1].toString()) {
console.log("pass")
} else {
console.error("failed")
}
if (getRow(1).toString() === [1, 1].toString()) {
console.log("pass")
} else {
console.error("failed")
}
if (getRow(2).toString() === [1, 2, 1].toString()) {
console.log("pass")
} else {
console.error("failed")
}
if (getRow(3).toString() === [1, 3, 3, 1].toString()) {
console.log("pass")
} else {
console.error("failed")
}
if (getRow(4).toString() === [1, 4, 6, 4, 1].toString()) {
console.log("pass")
} else {
console.error("failed")
}