Hi, this might be rare to come across, but
pywt.pad([1, 2, 3], 0, mode="antisymmetric")
pywt.pad([1, 2, 3], (2, 0), mode="antisymmetric")
pywt.pad([1, 2, 3], ((5, 0),), mode="antisymmetric")
pywt.pad([1, 2, 3], 0, mode="smooth")
pywt.pad([1, 2, 3], (1, 0), mode="smooth")
pywt.pad([1, 2, 3], ((4, 0),), mode="smooth")
Will all cause errors like
Traceback (most recent call last):
File "", line 63, in <module>
pywt.pad([1, 2, 3], 0, mode="smooth")
File "Anaconda3\lib\site-packages\pywt\_dwt.py", line 476, in pad
xp = np.pad(x, pad_widths, pad_smooth)
File "<__array_function__ internals>", line 5, in pad
File "Anaconda3\lib\site-packages\numpy\lib\arraypad.py", line 767, in pad
function(view[ind], pad_width[axis], axis, kwargs)
File "Anaconda3\lib\site-packages\pywt\_dwt.py", line 473, in pad_smooth
vector[-pad_width[1]:] = \
ValueError: could not broadcast input array from shape (0) into shape (3)
Ideally, a padding width of 0 should make pad an identity function. I noticed that only antisymmetric and smooth modes have this issue. Furthermore, the second 0 in the padding width pair seems to be the source of the problem, as pairs like (3, 0) work without errors.
Hi, this might be rare to come across, but
Will all cause errors like
Ideally, a padding width of 0 should make
padan identity function. I noticed that only antisymmetric and smooth modes have this issue. Furthermore, the second 0 in the padding width pair seems to be the source of the problem, as pairs like (3, 0) work without errors.