-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path26.py
More file actions
44 lines (34 loc) · 940 Bytes
/
Copy path26.py
File metadata and controls
44 lines (34 loc) · 940 Bytes
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
"""
A unit fraction contains 1 in the numerator. The decimal representation of
the unit fractions with denominators 2 to 10 are given:
1/2 = 0.5
1/3 = 0.(3)
1/4 = 0.25
1/5 = 0.2
1/6 = 0.1(6)
1/7 = 0.(142857)
1/8 = 0.125
1/9 = 0.(1)
1/10 = 0.1
Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle.
It can be seen that 1/7 has a 6-digit recurring cycle.
Find the value of d < 1000 for which 1/d contains the longest
recurring cycle in its decimal fraction part.
"""
def main():
print(solve(1000))
def solve(number):
prime_gen = gen_primes(number)
return max([next((x for x in range(1, number) if 10 ** x % prime == 1), 0)
for prime in prime_gen]) + 1
def gen_primes(number):
p = 2
yield p
primes = [p]
while p < number:
p += 1
if 0 not in [p % x for x in primes]:
primes.append(p)
yield p
if __name__ == "__main__":
main()