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package leetcode_1To300;
import java.util.PriorityQueue;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _313_SuperUglyNumber {
/**
* 313. Super Ugly Number
* Write a program to find the nth super ugly number.
Super ugly numbers are positive numbers whose all prime factors are in the given prime list
primes of size k. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32]
is the sequence of the first 12 super ugly numbers given primes = [2, 7, 13, 19] of size 4.
PriorityQueue kth
time : O(n * logk)
space : O(max(n,k))
* @param n
* @param primes
* @return
*/
public int nthSuperUglyNumber(int n, int[] primes) {
int[] res = new int[n];
res[0] = 1;
PriorityQueue<Num> pq = new PriorityQueue<>((a, b) -> (a.val - b.val));
for (int i = 0; i < primes.length; i++) {
pq.add(new Num(primes[i], 1, primes[i]));
}
for (int i = 1; i < n; i++) {
res[i] = pq.peek().val;
while (pq.peek().val == res[i]) {
Num next = pq.poll();
pq.add(new Num(next.prime * res[next.index], next.index + 1, next.prime));
}
}
return res[n - 1];
}
class Num {
int val;
int index;
int prime;
public Num(int val, int index, int prime) {
this.val = val;
this.index = index;
this.prime = prime;
}
}
}