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package leetcode_1To300;
import java.util.ArrayList;
import java.util.HashSet;
import java.util.List;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _187_RepeatedDNASequences {
/**
* 187. Repeated DNA Sequences
* All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T,
* for example: "ACGAATTCCG". When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.
Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.
For example,
Given s = "AAAAACCCCCAAAAACCCCCCAAAAAGGGTTT",
Return:
["AAAAACCCCC", "CCCCCAAAAA"].
time : O(n)
space : O(n)
* @param s
* @return
*/
public List<String> findRepeatedDnaSequences(String s) {
HashSet<String> seen = new HashSet<>();
HashSet<String> repeated = new HashSet<>();
for (int i = 0; i < s.length() - 9; i++) {
String temp = s.substring(i, i + 10);
if (!seen.add(temp)) {
repeated.add(temp);
}
}
return new ArrayList<>(repeated);
}
}